Re: populating a hash key using a variable

[Ian Zapczynski]

Yes, Rob, you are absolutely correct. Unfortunately, I still lack confidence in my coding abilities, so when something doesn't work, I seem to assume I just don't know how to do it properly. In reality, I just made a dumb mistake, which is partially where this lack of confidence comes from. :)

What I did was closer to this:

my $i = 0;
while (EXPR) {
$hash{KEY}{$i} = $something;
$i++;
# ok, so now let's test that I did this correctly
print $hash{KEY}{$i};
}

As you can see, silly me put my print statement AFTER I incremented the variable, so of course that key was undefined. Geez.
Precisely why I'm still on the "beginners" list. :)

Thanks James and Rob for helping me find that my error was not in syntax.

-I


Rob Dixon wrote:

Quite. What you've written looks fine Ian. But you've probably shown us what
you /meant/ rather than what you've actually coded :-}

Cheers,

Rob


----- Original Message -----
From: "Kipp, James" <[EMAIL PROTECTED]>
To: "'Ian Zapczynski'" <[EMAIL PROTECTED]>; <[EMAIL PROTECTED]>
Sent: Wednesday, December 11, 2002 4:11 PM
Subject: RE: populating a hash key using a variable

If I do $hash{SOMETHING}{0} = $something;

Then my hash is populated correctly. I am only not getting
results if I
do $hash{SOMETHING}{$i} = $something. The key here is how I am using
the variable $i in my hash.

I tried this on my machine and it worked fine:
my $i;
for ( 1..5 ) {
$hash{'KEY'}{$i} = "test$i";
print "$hash{'KEY'}{$i}\n";
$i++;
}
# prints:
test
test1
test2
test3
test4


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