> Hello. I have a logfile in which every message begins with a timestamp (ex. - 20012091500). I would like to be able to remove the last 4 characters (1500) off each of these to derive the date only (2001209). It works by chopping of each character individually, but I would like to know if there is a cleaner way to do this via regex or possibly by chopping multiple characters off at once.
> $ts = "200212091500"; > chop ($ts); > chop ($ts); > chop ($ts); > chop ($ts); > > print "$ts\n"; $ts = "200212091500"; $ts =~ s/(\d+)\d{4}/$1/; print "$ts\n"; -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]