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On Thu, 19 Dec 2002 17:44:22 +0100, "Jenda Krynicky" <[EMAIL PROTECTED]> wrote:
> From: [EMAIL PROTECTED]
> > ------------------------------------------------
> > On Thu, 19 Dec 2002 11:04:27 -0500, [EMAIL PROTECTED]
> > wrote:
> > > But is it not wrong to create an array in a function and send a
> > > reference to the array back into the main function?
> > >
> > > Because the scope of the array is limited to the function and
> > > calling a reference that is not available(the variables local in
> > > scope to the function are collapsed) must be illegal!!
> > >
> > > Regards,
> > > Satya
> >
> > You have just learned what a closure is :-). At least that is my
> > understanding of one.
>
> No this is not a closure.
>
> This is:
> sub createClosure {
> my $x = shift;
> return sub { print $x++,"\n" }
> }
>
> $closure = createClosure( 5 );
> $closure->();
> $closure->();
>
> Closure is a function that references a variable lexical to the scope
> it was created in even though the scope is long gone.
>
> Jenda
Obviously I never did quite get that. But your explanation makes sense to me. So it
is similar to what he had only rather than it being a reference directly (aka as a
scalar) to the other value, it is a reference to a subroutine that then accesses the
value?
http://danconia.org
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