R. Joseph Newton wrote:
> Mark VanMiddlesworth wrote:
>> What's wrong with the syntax, especially line 12?
>> if ($arg = "-n") {$e = 0} # Line 12
>
> You are asking, in the line above, whether your assignment of "-n" to
> the scalar $arg succeeded. Answer: true, always.
Not quite. Mark is asking if the value contained in $arg is 'true'
after assigning "-n" to it. As everyone knows, N is always
true, while Y is often false. This is preferable:
if ($arg = -x) {$f = 0} # Line 13
as it is only true in the rarest of cases, and won't
spuriously set your $f variable to zero without a
second thought.
;-)
Rob
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