According to the Perl Programming book, the $? is the status word returned by the wait(2) system call so the exit value of the subprocess is actually ($? >> 8). The >> operator is a binary shift right, where the left argument is shifted right the number of bits of the right argument.
Hope this helps. randy -----Original Message----- From: Nick Drage [mailto:[EMAIL PROTECTED] Sent: Thursday, June 12, 2003 3:08 PM To: [EMAIL PROTECTED] Subject: Re: $? On Thu, Jun 12, 2003 at 08:05:48PM +0200, Olivier Wirz wrote: > Hello, > > I would like to know if there is a way to check $? to see whether the > programm ran correctly in such a statement: > > @results =`grep $search $_`; $exitcode=$?; And there you have it, $exitcode is your exit code. I was given this answer by David van der Geer, who used: $exit_value = $? >> 8; I'm not sure what " >> 8 " means though, anyone? Also when I asked this Steve Grazzini advised: <quote> Nick Drage <[EMAIL PROTECTED]> wrote: > > > How do I capture the output and the exit code of a process? > > Basically I'm looking to combine the functionality of backticks > > and the system call. > Use backticks; and the wait() status that system returns will be in $?. </quote> -- ? -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED]
