Simple doublt of $_ and print;

[Chris San]

It is supose this code prints the first line of file text.txt (which is 
not empty), but it doesn't print anything.

$file = "text.txt";
open (file);
<file>;
print;
close (file);
I understood that  <file>;  gets a line (the first in this case) and, in 
this case, it puts the line in  $_ . Also,  print;  (without args) 
prints the content of $_ .

Any idea about it?

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