Last question on this, but, is there anything I should be aware of if I code
the Fred prog like this :

#!perl -w
$Add = 4;
$Mul = 2;
$Sub = 6;
$Div = 2;
$Append = 5;
$fred = 4;

print "Fred is now : $fred \n";
$fred += $Add;
print "Add 4 to Fred : $fred \n";
$fred *= $Mul;
print "Multiply by 2 : $fred \n";
$fred -= $Sub;
print "Subtract 6 : $fred \n";
$fred /= $Div;
print "Divide by 2 : $fred \n";
$fred .= $Append;
print "Append 5 to Fred : $fred \n";

-----Original Message-----
From: LoBue, Mark [mailto:[EMAIL PROTECTED]
Sent: 27 June 2003 00:51
To: 'Derek Byrne'; '[EMAIL PROTECTED]'
Subject: RE: Re : Compilation Errors


> -----Original Message-----
> From: Derek Byrne [mailto:[EMAIL PROTECTED]
> Sent: Thursday, June 26, 2003 4:44 PM
> To: 'LoBue, Mark'; Derek Byrne; '[EMAIL PROTECTED]'
> Subject: RE: Re : Compilation Errors
> 
> 
> Oopsie - just saw my own mistake, forgot to add the ; at the 
> end of the line
> preceding the last print.. Doh!
> Thank you Mark, just tried it again, and it works without the 
> '' surrounding
> the 5.. to be proper, should it have the ''?
> 

Perhaps perl is doing that for you also, it is just so smart, since the . is
a string operator, it converts both arguments to strings.

-Mark


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