Re: scalar to list conversion

[Steve Grazzini]

On Sat, Jun 28, 2003 at 06:38:34AM -0400, Steve Grazzini wrote:
> On Sat, Jun 28, 2003 at 11:04:33AM +0100, Rob Dixon wrote:
> > John W. Krahn wrote:
> > >
> > > @s = split ' ', $s;
> > 
> >   @s = split for $s

Erm, never mind my last post. :-)

      *_ = *s; split;

-- 
Steve

-- 
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]