----- Original Message -----
From: "B. Fongo" <[EMAIL PROTECTED]>
To: <[EMAIL PROTECTED]>; <[EMAIL PROTECTED]>
Sent: Thursday, September 04, 2003 11:34 AM
Subject: passing an argument to a subroutine
> Hello
>
> An argument passed to a subroutine returns wrong value.
What value do you want it to print?
>
> Code example:
>
> @x = (1..5);
> $x = @x;
Are you trying to get $x to contain "12345"?
Let's assume you want to pass the @x array into your subroutine and have it
print out it's contents from there.
Then I think this is what you want.
#!perl -w
@x = (1..5);
showValue (@x);
sub showValue {
my @forwarded = @_;
foreach(@forwarded){
print "$_\n";
}
}
What it really comes to is what value you want to pass to your subroutine.
>From reading your code, I can see that you are converting an array into a
scalar but is that really what you want?
Some more explanation of what you would like to acomplish would be nice.
>
> showValue ($x); # or showValue (\$x);
>
>
> sub showValue {
>
> my $forwarded = @_;
> print $forwarded; # print ${$forwarded};
>
> }
>
> In both cases, the script prints out 1.
> What is going on here?
>
> Thanks
>
> Babs
>
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