On Thu, Sep 25, 2003 at 09:12:48PM -0400, Dan Anderson wrote:
> If I create code with:
>
> BEGIN
> {
> # something
> BEGIN
> {
> # something else
> }
> }
>
> Will the inner BEGIN block take precedence over the outer one, and thus
> load any subroutines or whatever is in the inner begin block?
BEGIN blocks do not take precedence over one another--they are all
still executed. They are, however, executed immediately after perl
finishes compiling them. So, if you have the following code:
{
print "1\n";
BEGIN {
print "2\n";
BEGIN {
print "3\n";
}
}
print "4\n";
}
The output will be:
3
2
1
4
--Dks
--
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
