Try with $q->param("qty$i");
thereis no variable interpolation in '' but when u use "" variable interpolation
works.
regards,
KM
------------------------------------------------------------------
On Fri, Oct 31, 2003 at 01:01:49PM -0500, radhika sambamurti wrote:
> Hi,
> I am trying to do this:
>
> for( $i = 0; $i < 5; $i++) {
> $qty[$i] = $q->param('qty$i');
> }
> I could say $q->qty0;
> $q->qty1;
> |
> |
> |
> $q->qty4;
>
> and be done with it. That works. But I would rather do it from the loop.
> Why is my variable $i not being appended to qty form variable being passed?
> Any ideas?
>
> Thxs.
> Radhika
>
> --
> To unsubscribe, e-mail: [EMAIL PROTECTED]
> For additional commands, e-mail: [EMAIL PROTECTED]
>
--
--
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]