[ Please do not top-post. TIA ]
Christiane Nerz wrote:
>
> Nope - 'cause if I print out the values key for key, I get all four:
>
> my $array = keys %hash;
$array is a scalar and holds a single value. It is not related to
@array in any way.
> print $hash{$array[0]};
> print"\n";
> print $hash{$array[1]};
> print"\n";
> print $hash{$array[2]};
> print"\n";
> print $hash{$array[3]};
If you have 'strict' and 'warnings' turned on then perl would tell you
that @array doesn't exist for those four lines.
> With the code
> foreach (keys %hash) {
> print $hash{$_};
> print "\n";}
>
> I only get the value corresponding to $hash{$array[3]}.
It sounds like you are assigning a list to a scalar.
$scalar = ( 'one', 'two', 'three', 'four' );
In this case the comma operator will evaluate the first three items and
discard them and assign the fourth item to the scalar.
John
--
use Perl;
program
fulfillment
--
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
