On Thu, 2003-11-20 at 15:18, Jeff Kowalczyk wrote:
> I'm not yet able to read certain parts of perl code. What is this
> comparison/alternation after the hash lookup on 'otherid' called, and what
> does the code do?
>
> $myvar->{id} = ($myvar->{otherid}) ? 'stringA' : 'stringB';
>
> Thanks.
Jeff,
This is the if-then-else operator (for lack of a better term).
The code above could be translated to:
if ($myvar->{otherid}) {
$myvar->{id} = 'stringA';
} else {
$myvar->{id} = 'stringB';
}
>From 'perldoc perlop':
Ternary "?:" is the conditional operator, just as in C. It works much
like an if-then-else. If the argument before the ? is true, the argu-
ment before the : is returned, otherwise the argument after the : is
returned. For example:
printf "I have %d dog%s.\n", $n,
($n == 1) ? '' : "s"
HTH,
Kevin
--
Kevin Old <[EMAIL PROTECTED]>
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