I realised that the @ cannot enter in a string without escape characters. Is that equivalent to "
That's not quite true. Within double quotes, anything that looks like a variable is interpreted as a variable. So, 'print "@"' is perfectly fine. It does not look like a variable because '@' is not followed by a valid variable name. But in 'print "@at"', the '@' is interpreted as part of the variable '@at'. You can use a backslash ('print "[EMAIL PROTECTED]"') to escape or use single quotes ('print '@at'') to prevent the interpolation.
Regards, Randy.
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