Re: why $a became 6 ?

[Steve Grazzini]

Jayakumar Rajagopal wrote:
($a=3 && $b=6 ) if ( 1 == 1 );
print " $a   $b  \n";
Output : 6   6  
This is a precedence problem; the "&&" binds more tightly
than the "=" on its left.  B::Deparse eliminates some of
the constant expressions, but you can see the result:
    % perl -MO=Deparse,-p -e '$a=3 && $b=6'
    ($a = ($b = 6));
    -e syntax OK
Or to break it down another way:

    $a = 3 && $b = 6;
    $a = 3 && 6;
    $a = 6;
Any of these will do what you probably wanted:

    $a = 3 and $b = 6;
    ($a, $b) = (3, 6);
    ($a = 3) && ($b = 6);
--
Steve
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