Thank you for replying. The only thing is that when I shouldn't be escaping the right paren since they indicate the variable $1 to be printed below. I tried escaping the paren but it results in a nonmatch. Could you let me know if I am looking at it incorrectly? Thanks again. Ahmer
-----Original Message----- From: Anders Holm [mailto:[EMAIL PROTECTED] Sent: Monday, June 21, 2004 8:22 AM To: Khan, Ahmer H Cc: [EMAIL PROTECTED] Subject: Re: Using regular expression as a variable. Hi. See inline comments.. [snip] > Here is my code. > > 1 $filename = 'This is a directory\file\sub.txt'; > 2 $regex = '\\(\w+\.\w+)$'; $regex = '\\(\w+\.\w+\)$'; Missed to escape the last ) ... [snip] > However if I "copy/paste" the actual regexp from line 2 into line 3 > and not use the variable, the program works fine. Yes, single versus double quotes.. may want to look up the differences.. :D Leaving that as an exercise for the reader.. //Anders// -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] <http://learn.perl.org/> <http://learn.perl.org/first-response>
