On Tue, 21 Sep 2004 14:58:43 -0400 (EDT), Jeff 'japhy' Pinyan
<[EMAIL PROTECTED]> wrote:
> On Sep 21, Bob Showalter said:
>
> > my %hash = (
> > foo => 1,
> > bar => 2,
> > baz => 3,
> > qux => 4,
> > );
> >
> >I would like to remove all the entries in the hash except for 'bar' and
> >'qux'. (Actual hash has other entries which can vary at runtime. I know that
> >I only want to keep 'bar' and 'qux' however).
>
> > my @keys = qw(bar qux);
>
> You could do:
>
> my %keep_these_keys;
> @keep_these_keys{qw( bar qux )} = ();
>
> delete @hash{ grep !exists $keep_these_keys{$_}, keys %hash };
>
> --
> Jeff "japhy" Pinyan % How can we ever be the sold short or
> RPI Acacia Brother #734 % the cheated, we who for every service
> http://japhy.perlmonk.org/ % have long ago been overpaid?
> http://www.perlmonks.org/ % -- Meister Eckhart
>
>
So ... is there a way to return a 'not' slice of hashes? What I mean
is, the 'keys' function returns a list of all keys in a slice. Is
there a function to return a list of all keys in slice EXCEPT those
keys that I explicitely pass? like this, maybe:
my %my_hash = (
foo => 1,
bar => 2,
baz => 3,
qux => 4,
);
my @other_keys = not_keys( %my_hash, "foo", "bar" )
and then @other_keys = qw( baz qux )
???
--Errin
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