[EMAIL PROTECTED] (Denham Eva) wrote in news:[EMAIL PROTECTED]:
> Hello Gurus, > In a script I have a piece of code as such:- > ************* snip************** > my $filedate =~ s/(\d+)//g; > ************* snip end ******* > The data I am parsing looks as such :- > ********** DATA ************ > > C:/directory/MSISExport_20040814.csv > > C:/directory/MSISExport_20040813.csv > > . > > C:/directory/MSISExport_20030501.csv > > ********** DATA end ********* > Now I am actually trying to dump everything except the date or numerals > as such :- 20040814 > > Can someone help me with that regex? I am having a frustrating time of > it! > > Much appreciated > > Denham Denham, If you have the filename in a scalar called $filename then the code to place the date into a scalar called $filedate would be: ($filedate) = $filename =~ m|MSISExport_([0-9]+)\.csv|; This places the captured value in ([0-9]+) into $filedate. This doesn't catch an instance where the filename is malformed and that date doesn't exist there. Hope this helps, Bill -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] <http://learn.perl.org/> <http://learn.perl.org/first-response>
