Apparently, the first command spawns a new shell when it is executed
and the control is never returned back and hence i cannot get the
second command to get executed.
So I am trying to evaluate the -exec option.
Thanks.
On Thu, 3 Mar 2005 16:14:30 -0800, Wagner, David --- Senior Programmer
Analyst --- WGO <[EMAIL PROTECTED]> wrote:
> Nishi Prafull wrote:
> > Hi:
> > Apparently I noticed that when I put both the commands I need to run
> > in one script using the system call, the second command does not get
> > executed ( I cannot figure out the cause).
> They would have to be two separate calls. I used to start 10 to 15
> processes at one time using a Perl script to get my setup the way I wanted
> it. Then I knew exactly where they were and the order they were in.
>
> So you only need to do;
>
> my $MyStatus1 = system('script1.pl'); # make sure you qualify the
> script as much as necessary and not rely on
> # paths.
> # should check that status was a success which i believe is backwards
> from what Perl defines as success(0: good, <> # 0:error)
>
> my $MyStatus2 = system('script2.pl'); # second one to execute.
>
> Wags ;)
> > Each of the commands are making out calls to software installed on the
> > machine to perform specific tasks.
> >
> > Do I have to do anything else in this regard?
> >
> > Thanks.
> >
> > On Thu, 3 Mar 2005 15:50:16 -0800, Tim Johnson <[EMAIL PROTECTED]>
> > wrote:
> >>
> >> I guess it partly depends on what you are trying to accomplish. Why
> >> are you calling a second script?
> >>
> >>
> >> -----Original Message-----
> >> From: Nishi Prafull [mailto:[EMAIL PROTECTED]
> >> Sent: Thursday, March 03, 2005 3:47 PM
> >> To: [email protected]
> >> Subject: call a perl script within another perl script
> >>
> >> Hi:
> >> I would like to call a perl script(B.pl) within another perl
> >> script(A.pl). Should I use the following approach or something else?
>
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