Hi,
I have to do some log processing with webalizer and tried to do the following:
#!/usr/bin/perl
use strict;
use warnings;
opendir(DIR, "/Users/jan/Sites/apache_logs") or die "Cannot open directory";
while (defined(my $file = readdir(DIR))) {
if ($file =~ /^www/) {
print "Processing $file ... \n";
system ("webalizer", "-c ./webalizer.conf",
"/Users/jan/Sites/apache_logs/$file");
}
}
closedir(DIR);
webalizer complains that it cannot find the configuration file (provided via
the -c parameter).
But when I issue
webalizer -c ./webalizer.conf /Users/jan/Sites/apache_logs/www.20040215
in bash, the configuration file is found without a problem.
Why is that? My system syntax should be correct - and webalizer does recognize
the filename. The configuration file is in the same directory as the Perl
script. But in any case, the problem persists if I specify an absolute path to
the configuration file within the script.
Grateful for any hint,
Jan
--
There are two major products that come out of Berkeley: LSD and UNIX. We don't
believe this to be a coincidence. - Jeremy S. Anderson
--
To unsubscribe, e-mail: [EMAIL PROTECTED]
For additional commands, e-mail: [EMAIL PROTECTED]
<http://learn.perl.org/> <http://learn.perl.org/first-response>
