Hello
i am having something like this ...
$b = "\xa0\xa0\xa0\x{100}" =~ /(\xa0+)/;
$b =~ \(\xa0+)\;
print "Valid" if ($1 eq "\xa0\xa0\xa0";
print " $b $1";
Here according to the regular expression the $1 should contain the matching
string. so according $1 should have \xa0\xa0\xa0. This is happening in ASCII
platform but it is not working in the EBCIDIC.
as x{100} is 2 byte character, \xa0 will also get converted to double byte
which is valid. The strange thing is in $1 \xa0 is 4 bytes.
Why is that $1 is containing 4 bytes, why data is not correct.
PS: all these is happening only in EBCIDIC platform. in ASCII it is fine.
Failure is the step for success. If you know you are failed it will be easy to
climb step.
---------------------------------
Too much spam in your inbox? Yahoo! Mail gives you the best spam protection
for FREE!
http://in.mail.yahoo.com
