Siegfried Heintze wrote:
The following code works with perl/MySQL. If I comment the second
line, however, it does not work. No error messages and no results.
If I use the MySQL Enterprise console and type in my first SELECT
statement that includes the LIKE clause, it works.
I'm stumped. There must be something strange with that "%", but I
cannot figure it out.
Anyone got any suggestions?
Siegfried
my $sJobTitle = q[SELECT sName FROM keywords ORDER BY sName WHERE
sName LIKE '%'];
That should raise an error. WHERE clause needs to come befor ORDER BY
clause.
Unless you have RaiseError turned on, you aren't checking for errors below.
$sJobTitle = q[SELECT sName FROM keywords ORDER BY sName];
my $sth = DBH->prepare($sJobTitle);
$sth->execute();
my $row;
while ($row = $sth->fetch){
push @sResult,"<li>".join( "", @$row)."</li>\n";
}
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