Dave Adams wrote:
Does perl allow you to conditionally include a module?
For example:
#!/usr/bin/perl -w
use strict;
my $DEBUG = 0;
if (DEBUG) {
use diagnostics;
}
my $filename = "test$$.txt";
open (FH , ">$filename") || die "error: $!";
print (FH "hi");
close (FH);
Although this is a simple and silly example, it would be nice to be
able to include the diagnostic module by setting my debug to true.
Any Comments?
DA
If you're using Perl 5.7.3 or later you can
use if $DEBUG, diagnostics -verbose;
details in 'perldoc if'
:)
And all you people who answered with something other than this, aren't you
ashamed you didn't know about 'if' ? :)
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