On 8/9/2005 6:26 AM, Paul Johnson wrote:
> my @s = map { $_ -> [0] }
> sort { $a->[0] <=> $b->[0] ||
> $a->[1] <=> $b->[1] ||
> $a->[2] <=> $b->[2] ||
> $a->[3] <=> $b->[3] }
> map { [ $_, split /\./ ] }
> map { $_->{N} } @a;
You clearly solved the problem that I asked, but... :)
I've apparently dumbed down my code and question a bit too much: I have
multiple hashrefs in each element of the array, and I need the resulting
sorted array to contain all the data in the original array, simply
sorted by the value of N.
my @a = ( {N => '10.1.2.1', ID => 1},
{N => '10.1.9.1', ID => 2},
{N => '10.3.5.1', ID => 3},
{N => '10.1.1.3', ID => 4},
);
When I use your suggested code, only the value of N seems to be in @s.
Thanks for your help, Paul.
--
Jeremy Kister
http://jeremy.kister.net./
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