Perl wrote: > I am new to perl so I need some help from the list with this script. > It takes a value from command line and then returns afters processing. > For example, If value is "c:\projects\test 2005.txt" the script will > returns it as "test" (actually omitts any space in the directory or > file name) while I want the full name of the file regardless of any > space in the directory or filename. > how can I get the value "test 2005.txt"? > > #!/usr/bin/perl > # file: basename.pl > use strict; > use File::Basename; > my $path = $ARGV[0]; > my $base = basename($path); > my $dir = dirname($path); > print STDOUT $base; > > > any help will be greatly appreciated. > > Thanks in advance.
It works for me: C:\>perl -MFile::Basename -e"print basename q(c:\projects\test 2005.txt)" test 2005.txt How are you executing the script? Are you surrounding c:\projects\test 2005.txt with quotes when you call the script? If not, $ARGV[0] will only contain "c:\projects\test". Why not put a "print join ':', @ARGV" in your script and you'll see what I mean. -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] <http://learn.perl.org/> <http://learn.perl.org/first-response>
