On Sep 14, Luinrandir said:
but what if I want to pass a var? then
$glob->($foo,$bar);
?????
But I still have no clue as to why this works... esp.
$glob->();
just looked in my book.. am I dereferencing a reference?
Basically, yes. $glob ends up being a glob, a reference to everything
with that name (in your case, a reference to everything named 'HTML' in
the Inn:: or Castle:: or Whatever:: class). When you do $foo->(...),
you're saying that $foo holds a reference to a function, and you want to
call the function. Since what's in $glob is a glob, a reference to every
type (scalar, array, hash, etc.), we do $glob->(ARGS).
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