Sorry,I really didn't know this regex written by John: /^User:\s*(.+?)$(?=.*=([^[]+)\[)/sm;
Can anyone explain for that?thanks. 2005/11/17, Jeff Pang <[EMAIL PROTECTED]>: > Sorry,I can't understand for this RE too.John explain that pls. > > 2005/11/17, S, karthik (IE03x) <[EMAIL PROTECTED]>: > > John and Jeff, > > > > Could you please explain the RE used. > > > > /^User:\s*(.+?)$(?=.*=([^[]+)\[)/sm; > > > > I understood that it looks for 'User:\s'. Then I am not able to figure > > out the meaning of the remaining part of RE. > > > > > > With Best Regards, > > > > Karthikeyan S > > > > > > > > -----Original Message----- > > From: Jeff Pang [mailto:[EMAIL PROTECTED] > > Sent: Thursday, November 17, 2005 2:06 PM > > To: John W. Krahn > > Cc: Perl Beginners > > Subject: Re: How to get this hash? > > > > Thanks for John.I have tested it,it is good for me. > > > > 2005/11/17, John W. Krahn <[EMAIL PROTECTED]>: > > > Jeff Pang wrote: > > > > Hi,lists, > > > > > > Hello, > > > > > > > I have a file that look as: > > > > > > > > -- > > > > User: honorhr40 > > > > Got data from YY23 (md1=23,md2=24): > > > > [0] xxxx=46[I:0 T:Int] > > > > [1] pd=[I:0 T:Str] > > > > [2] cosnm=normal[I:0 T:Str] > > > > -- > > > > User: lulu-918 > > > > Got data from YY18 (md1=18,md2=19): > > > > [0] xxxx=69[I:0 T:Int] > > > > [1] pd=back.zzz.com[I:0 T:Str] > > > > [2] cosnm=normal[I:0 T:Str] > > > > > > > > ...... > > > > > > > > and thousands of these lines. > > > > > > > > I want to get the No.1 line and No.5 line,just as: > > > > > > > > User: honorhr40 > > > > [2] cosnm=normal[I:0 T:Str] > > > > > > > > and put the two lines into a hash,as: > > > > > > > > $hash{'honorhr40'} = 'normal'; > > > > > > > > I have no ideas on doing this work.Can you anyone give me some > > help?thanks. > > > > > > This appears to do what you want: > > > > > > #!/usr/bin/perl > > > use warnings; > > > use strict; > > > use Data::Dumper; > > > > > > $/ = "--\n"; > > > > > > my %hash; > > > > > > while ( <DATA> ) { > > > > > > next unless /^User:\s*(.+?)$(?=.*=([^[]+)\[)/sm; > > > > > > $hash{ $1 } = $2 > > > } > > > > > > print Dumper \%hash; > > > > > > __DATA__ > > > > > > -- > > > User: honorhr40 > > > Got data from YY23 (md1=23,md2=24): > > > [0] xxxx=46[I:0 T:Int] > > > [1] pd=[I:0 T:Str] > > > [2] cosnm=normal[I:0 T:Str] > > > -- > > > User: lulu-918 > > > Got data from YY18 (md1=18,md2=19): > > > [0] xxxx=69[I:0 T:Int] > > > [1] pd=back.zzz.com[I:0 T:Str] > > > [2] cosnm=normal[I:0 T:Str] > > > > > > > > > > > > John > > > -- > > > use Perl; > > > program > > > fulfillment > > > > > > -- > > > To unsubscribe, e-mail: [EMAIL PROTECTED] > > > For additional commands, e-mail: [EMAIL PROTECTED] > > > <http://learn.perl.org/> <http://learn.perl.org/first-response> > > > > > > > > > > > > > -- > > To unsubscribe, e-mail: [EMAIL PROTECTED] > > For additional commands, e-mail: [EMAIL PROTECTED] > > <http://learn.perl.org/> <http://learn.perl.org/first-response> > > > > > > > -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] <http://learn.perl.org/> <http://learn.perl.org/first-response>
