On Sun, 11 Dec 2005, Octavian Rasnita wrote: > Can anyone explain why: > > $i++; > > is faster
Not that I know for sure, but I'd imagine the explanation is that, deep in the bowels of Perl, the ++ operator is optimized in a way that a more generic operator like += or = can't be. But I could be wrong. How much faster is it? -- Chris Devers ~Ò#Gn¹$¬äð
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