John W. Krahn wrote:
Rob Dixon wrote:If you miss out the comma with print $1 "\n" then Perl looks at this as a method call on $1 as an IO::Handle object, or $1->print("\n");No. perldoc -f print print FILEHANDLE LIST print LIST print Prints a string or a list of strings. Returns true if successful. FILEHANDLE may be a scalar variable name, in which case the variable contains the name of or a reference to the filehandle, thus introducing one level of indirection. If the comma is missing then the first scalar or bareword argument is treated as a filehandle.
Hmm. Well if I was wrong I'd like to be corrected, but it certainly /looks/ and /behaves/ like indirect-object method call syntax, and the equivalent arrow syntax works and does the same thing. But whether it's really a method call under the hood I'm not absolutely certain, especially when there are oddities like print(STDOUT "text\n"); working fine. Whatever it is, it certainly stops being either a list operator or a function call, so what else can it be? Rob -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] <http://learn.perl.org/> <http://learn.perl.org/first-response>
