Re: Command line vs. cron

[James Marks]

On Sep 12, 2006, at 9:59 PM, Owen Cook wrote:
Here's the script:

#!/usr/bin/perl

use warnings;
use strict;

my $log_file = '/home/james/code/cron_code/httpsd_mysqld_log_file';

open FILE_OUT, ">> $log_file"
     or die "Cannot open log file: $!";

select FILE_OUT;

(my $month, my $day, my $year, my $hour, my $minute, my $second) =
(localtime)[4, 3, 5, 2, 1, 0];

printf("%04s-%02s-%02s %02d:%02d:%02d ", $year+1900, $month, $day,
$hour, $minute, $second);

my $httpsd_count = `ps -aux | grep -c httpsd`;
my $mysqld_count = `ps -aux | grep -c mysqld`;

chomp($httpsd_count);
chomp($mysqld_count);

my $httpsd_msg = '';
my $mysqld_msg = '';

if ($httpsd_count > 0) {
     print "httpsd $httpsd_count ";
}
else {
     print "httpsd NOT RUNNING ";
}

if ($mysqld_count > 0) {
     print "mysqld $mysqld_count ";
}
else {
     print "mysqld NOT RUNNING ";
}

print "\n";

close FILE_OUT;



I suspect that your env includes the path to "ps"

For cron you would need the full path

Try
 my $httpsd_count = `/usr/bin/ps -aux | grep -c httpsd`;
 my $mysqld_count = `/usr/bin/ps -aux | grep -c mysqld`;

I just tried that and let it run in cron but there's no difference in 
output. I still get "1"s in cron and process counts from the command 
line.

cron:
2006-08-12 22:15:20 httpsd 1 mysqld 1

command line:
2006-08-12 22:19:18 httpsd 19 mysqld 30


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