--- Rob Dixon <[EMAIL PROTECTED]> wrote:
> Derek B. Smith wrote:
> > --- "Dr.Ruud" <[EMAIL PROTECTED]> wrote:
> >
> >> Norbert Preining schreef:
> >>
> >>> The Perl Book says: Auto increment and decrement
> >> work as in
> >>> C. So if I take this C program:
> >>> #include <stdio.h>
> >>> #include <stddef.h>
> >>> int main() {
> >>> int a;
> >>> int b;
> >>> a=3;
> >>> b=(++a)+(a++);
> >>> printf("b=%d\n",b);
> >>> }
> >>> it prints b=8.
> >>>
> >>> When I do the same in perl:
> >>> $a = 3;
> >>> $b = (++$a) + ($a++);
> >>> print "b=$b\n";
> >>>
> >>> It prints b=9.
> >>>
> >>> I checked with a friend and Java behaves like C
> >> and prints 8.
> >>
> >> $ perl -wle '
> >> $a = 3;
> >> $b = 0 + (++$a) + ($a++);
> >> print "b=$b\n";
> >> '
> >> b=8
> >> :)
> >
> >
> > Lessons learned....
> >
> > always initialize your variables to zero. : )
>
>
> That's not initialising the variable, its, sort of,
> initialising the expression.
>
> $b = 0;
> $b += ++$a + $a++;
>
> (the parentheses are irrelevant) also gives 9. This
> looks like a bug to me, and
> v5.6 does it as well. Unless anyone can persuade me
> that this is correct
> behaviour?
>
> Rob
>
No I cannot, you are correct...init the expression. :
)
Have to remember this one.
I tried in on Active Perl 5.8.8 and Cygwin 5.8.7 and
it is behaving the same way.
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