----- Original Message ---- From: D. Bolliger <[EMAIL PROTECTED]> To: beginners@perl.org Sent: Sunday, January 21, 2007 7:43:19 PM Subject: Re: putting ";" as a replacement in the substitution.
> Because everything matched - that is: vd=\w+(,) - is replaced with the > semicolon. > You seem to misunderstand the meaning of the capturing parenthesis '()' on > the > left part of the substitution: They do not indicate the part of the string > that is to be replaced; replaced is what the left side of the substitution > matches. I see... so in substitutions, all patterns in the left side are those that have to be substituted, regardless of which is enclosed in parenthesis. However in a plain regexp look ups, only those inside the parenthesis are being matched... I tried explaining my experiment here. http://www.mail-archive.com/beginners%40perl.org/msg82761.html > And how to get around with it.. One way is: $string =~ s/(vd=\w+),/$1;/; It did work, as someone has already suggested. Thanks. Now, it's a lot clearer. > There are several man pages, where also the capturing parenthesis and the $1.. > $n variables are explained: > perldoc perlre > perldoc perlretut > perldoc perlrequick > Hope this helps! Dani -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] http://learn.perl.org/ ____________________________________________________________________________________ Looking for earth-friendly autos? Browse Top Cars by "Green Rating" at Yahoo! Autos' Green Center. http://autos.yahoo.com/green_center/
