Hi, On 2007/02/26, at 11:08, [EMAIL PROTECTED] wrote:
The above code does not seem to work for me. I get an error saying $" is unrecognised. do i need to include anything ?
Actually, I'm using Perl 5.8.8. I don't know if 5.6 or lower has that variable. Actually, it does. If you are on unix you can try this:
$ perl -e '@a = qw(1 2 3 4); { local $" = "\n"; print "@a" }' The output will be like this: 1 2 3 4 From "perldoc perlvar": $LIST_SEPARATOR$" This is like $, except that it applies to array and slice val- ues interpolated into a double-quoted string (or similar inter- preted string). Default is a space. (Mnemonic: obvious, I
think.) HTH! -- Igor Sutton [EMAIL PROTECTED]
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