On 8/31/07, Hunter Barrington <[EMAIL PROTECTED]> wrote:
> is there a type() function in perl? i need to be able to test the
> contents of an array and
> if (type($value)=='string' or type($value)=='int') {print "i win";}
You probably meant to use the 'eq' (string equality) comparison
operator instead of the '==' (numeric equality) operator. But there's
no type() function, because Perl doesn't have a concept of "type" like
yours. A variable can be both an integer and a string at the same
time.
Here's a FAQ entry that may help:
http://perldoc.perl.org/perlfaq4.html#How-do-I-determine-whether-a-scalar-is-a-number%2fwhole%2finteger%2ffloat%3f
Does that help with your problem? Cheers!
--Tom Phoenix
Stonehenge Perl Training
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