jrpfinch wrote:
I would like to execute the following regex on a file:
s/(\$Revision:\s+)(\d+\.\d+)(\s+\$.+use constant VERSION\s+=> ")(.+?)
(")/$1$2$3Revision $2$5/gs
I am doing this in bash as follows:
REGEX='s/(\$Revision:\s+)(\d+\.\d+)(\s+\$.+use constant VERSION\s+=> ")
(.+?)(")/$1$2$3Revision $2$5/gs'
REGEX="'"$REGEX"'"
perl -p0777 -e $REGEX mmScheduler.pl > mmScheduler.ed
Unfortunately I am getting the error and can't seem to find the source
of it after a few experiments:
Can't find string terminator "'" anywhere before EOF at -e line 1.
Any advice gratefully received.
Doesn't work here either. :-)
$ REGEX='s/(\$Revision:\s+)(\d+\.\d+)(\s+\$.+use constant VERSION\s+=>
")(.+?)(")/$1$2$3Revision $2$5/gs'
$ REGEX="'"$REGEX"'"
$ perl -MO=Deparse -pe $REGEX
LINE: while (defined($_ = <ARGV>)) {
'???';
}
continue {
print $_;
}
-e syntax OK
Here is what you need to do:
$ REGEX=' s/(\$Revision:\s+)(\d+\.\d+)(\s+\$.+use constant VERSION\s+=>
")(.+?)(")/$1$2$3Revision $2$5/gs '
$ perl -MO=Deparse -pe $REGEX
LINE: while (defined($_ = <ARGV>)) {
s/(\$Revision:\s+)(\d+\.\d+)(\s+\$.+use constant VERSION\s+=>
")(.+?)(")/$1$2$3Revision $2$5/gs;
}
continue {
print $_;
}
-e syntax OK
John
--
Perl isn't a toolbox, but a small machine shop where you
can special-order certain sorts of tools at low cost and
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