Can somebody please help me on following doubt.....
--Irfan. -----Original Message----- From: Sayed, Irfan (Irfan) Sent: Friday, October 19, 2007 4:49 PM To: 'Siva Prasad' Subject: RE: Regular expression But still my doubt exist. How Perl knows that it has to stop at the @ character As per your suggestion , I have written like this. my $project="aic_8.0wewew@/vobs/pvob_aic"; print "$project\n"; my ($pvob) = ($project =~ m{(.+@)}); print "$pvob\n"; and now it is taking @ in output so now how Perl knows that it has to stop at @ character. As per my understanding, (.+) this means any character with any no. of times then why it is not taking all the character. why the output is not coming as "aic_8.0wewew@/vobs/pvob_aic" and why it is coming as aic_8.0wewew@ Please help. Regards Irfan. -----Original Message----- From: Siva Prasad [mailto:[EMAIL PROTECTED] Sent: Friday, October 19, 2007 4:15 PM To: Sayed, Irfan (Irfan) Subject: RE: Regular expression This is because you have given @ outside () and the string that is there inside the '()' is moved to $pvob.(i..e the first matched string in the right hand side is moved into the first variable on the left hand side. Try this by giving '@' inside the '()' the you will also get '@' in pvob. '()' tells the first matched string. Tyr the below my $string="aic_8.0@/vobs/pvob_aic"; my $pvob = ($string =~ m{(.+)@}); print "$1\n"; $1 represents string that is matched inside the first '()' occurrence. Thanks, Siva -----Original Message----- From: Sayed, Irfan (Irfan) [mailto:[EMAIL PROTECTED] Sent: Friday, October 19, 2007 4:01 PM To: beginners@perl.org Subject: Regular expression Hi All, I have one string aic_8.0@/vobs/pvob_aic which is stored in one variable $project Now I need only that part of that string which is before @ so I have written following regular expression to achieve this... my ($pvob) = ($project =~ m{(.+)@}); and with the help of this reg. exp. I am achieving the expected result as aic_8.0 but my doubt is that how Perl knows that it has to stop collecting all the characters till @ character comes and don't include @ character in output Please help. Regards Irfan. -- To unsubscribe, e-mail: [EMAIL PROTECTED] For additional commands, e-mail: [EMAIL PROTECTED] http://learn.perl.org/