On 10/26/07, yitzle <[EMAIL PROTECTED]> wrote:
> @re = $x=~/(\w+;\w+);{0,1}/g;
> Array @re holds the resulting matches (inside the brackets) of the
> RegEx $x=~/(\w+;\w+);{0,1}/g
>
> $x=~/(\w+;\w+);{0,1}/g
> the /g means don't stop after one match.
>
> /(\w+;\w+);{0,1}/
> \w is a "word"
> This matches one or more word(s) followed by a semicolon, again one or
> more words, the 0 or 1 semicolons - the greater of the two, I suppose;
> this allows you to not end in a semicolon.
> I suspect the {0,1} would have the same affect as ?
\w matches a word character as Perl defines them (alphanumeric and the
underbar character), \w+ matches one or more of them. Perl's
definition may not match yours (e.g. "can't" isn't a word because the
single quote/apostrophe character is neither alphanumeric nor an
underbar).
from perldoc perlre
A "\w" matches a single alphanumeric character (an alphabetic
character, or a
decimal digit) or "_", not a whole word. Use "\w+" to match a
string of Perl-
identifier characters (which isn't the same as matching an
English word). If
"use locale" is in effect, the list of alphabetic characters
generated by "\w"
is taken from the current locale. See perllocale.
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