2008/7/14 Rob Dixon <[EMAIL PROTECTED]>:
>
> Dermot wrote:
>>
>> I am trying to build a hash(ref) and while doing so I want to remove
>> any white space from strings such as "1280 x 1024". So I have
>>
>> my $record = {
>> contributor => $resolution,
>> ....
>> };
>>
>> Perhaps I am trying to be too clever but I thought I could do
>>
>> my $record = {
>> contributor => $resolution =~ s/\s+//g,
>>
>>
>> But my value ends up as 2, the number of white space matches I guess.
>> Is this a question on context, scalar or list? Or is this sort of
>> assignment over-stretching things?
>
> The substitution operator alters the object string and returns the number of
> changes, as you have found. You could write
>
> ($record{contributor} = $resolution) =~ s/\s+//g;
>
> or perhaps
>
> my $record = {
> contributor => do {$resolution =~ s/\s+//g; $resolution},
> };
>
> HTH,
The do method worked. I guess that makes it into a sub which is fine.
BTW, have I told you what a star you are? You have replied to every
item that's come onto the list. Well done.
Dp.
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