Xavier Mas schreef:
> Dr.Ruud:
>> Xavier Mas:

>>> m#(pattern)#;
>>> $variable= $1.;
>>
>> That can be written as:
>>   ($variable) = /(pattern)/;
>
> Thank you for pointing that, Dr. Ruud but, what does mean
> ($variable)?.

  /(pattern1).*?(pattern2)/ returns the matches in list context, and the
number of matches (so 0 or 2) in scalar context.

Just try it with some test code.

-- 
Affijn, Ruud

"Gewoon is een tijger."


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