Dr.Ruud wrote:
> Rob Dixon schreef:
>> Kelly Jones:
>>>
>>> Consider:
>>>
>>> perl -le '$hash{"foo-bar"} = 1; print $hash{foo-bar}'
>>> [no result]
>>>
>>> perl -le '$hash{"foobar"} = 1; print $hash{foobar}'
>>> 1
>>>
>>> I sort of understand this: in the first script, Perl treats foo-bar
>>> as a subtraction, and sets $hash{0} to 1. In the second one it
>>> assumes you just left off some quotes.
>>>
>>> My question: since Perl doesn't have constants, what exactly IS
>>> foo-bar? Why is it 0?
>>>
>>> The behavior above seems inconsistent to me. Is it considered a bug?
>>
>> I have said that I have no time for command-line perl. What you have
>> published doesn't work on my platform, nor on many others.
>>
>> Of course I could rewrite the question in my head to a proper Perl
>> program, but then I shall be looking for a bug either in my mental
>> rewrite or in your original code.
>>
>> So since you can't be bothered to publish a proper Perl program,
>> neither can I be bothered to interpret your question. What is more,
>> nor will all the other people who could have answered your question
>> wisely.
>
> Rob, start sparing us this. Perl isn't what you (and I) limit it to.
I agree this did seem uncommonly grumpy of me. In particular I chose a bad
example to criticize (although I still would have preferred to see just the Perl
code rather than the entire command line).
So I apologise, and will keep my comments better in context in the future.
Rob
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