> -----Original Message-----
> From: jeffqt...@gmail.com [mailto:jeffqt...@gmail.com]
> Sent: Friday, January 23, 2009 12:58
> To: beginners@perl.org
> Subject: Loading results of pattern match into an array - help please
>
> I am trying to split a very long fixed lenght record into its
> constituents, and then load them into an array. I have
> patterns like '^
> (.{3})(.{24})(.{6})...' which gets teh fields into $1, $2, $3 etc. I
> am stumped however as to how to get them into an array in a general
> way. With 'use strict' turned off I can force it with the ugly ${$i}
> construct in a loop, but I would prefer something that was 'strict'
> compatible. I havebasic. read the perodlc on @-, %-, %+, and none seem
> to do what I want - but that probably because I am missing something
it does a double regex and one of the gurus can probably do it
without the double, but this does work:
#!/usr/bin/perl
use strict;
use warnings;
my @MyWorka = ();
while ( <DATA> ) {
chomp;
next if ( /^\s*$/ );
if ( /(\d+)\s+(\d+)\s+(\d+)\s+(\d+)\s+(\d+)/ ) {
@MyWorka = (/(\d+)\s+(\d+)\s+(\d+)\s+(\d+)\s+(\d+)/);
printf "<%s>\n",
join(q[|], @MyWorka );
}
else {
printf " not correct number of fields on line to load into
array:\n";
printf "(%6d)<%s>\n",
$.,
$_;
}
}
__DATA__
1234 1234 1235 1236 1237
1234 1234 1235 1236
Output:
<1234|1234|1235|1236|1237>
not correct number of fields on line to load into array:
( 3)<1234 1234 1235 1236>
>
> So, any help gratefully accepted
>
> Jeff
>
>
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