freefox <robert.lo...@privat.utfors.se> asked:
> As join is a build in I guess it should/could be called without
> parenthesis.
> However these two lines gives me two different answers.
>
> my @strings = ('foo', 'bar');
>
> my $string1 = q{('} . join q{', '}, @strings . q{')};
> my $string2 = q{('} . join(q{', '}, @strings) . q{')};
>
> print "$string1\n";
> print "$string2\n";
>
> Output:
> ('2')
> ('foo', 'bar')
>
> Anyone who knows/understands why?
See http://perl.plover.com/context.html for a complete explanation.
HTH,
Thomas
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