Courtesy of OddsShark.com The Baltimore Orioles and the Boston Red Sox will both be trying to pick up a win on Tuesday when they battle at Fenway Park. The Orioles will give the ball to starter Rick Vanden Hurk in this one. Righthander Vanden Hurk is 0-0 this season with a 11.59 ERA. The Red Sox will counter Vanden Hurk with Erik Bedard. Lefthander Bedard has a 3.50 ERA to go along with a 5-9 record this season. Oddsmakers currently have the Red Sox listed as 250-moneyline favorites versus the Orioles, while the game's total is sitting at 10½. Last time out for Baltimore, they were a 18-9 loser as they battled the Red Sox on the road. Moneyline bettors who got the Red Sox at -237 were rewarded, while the 27 combined runs moved the game OVER for totals bettors. Team records: Baltimore: 63-90 SU Boston: 88-66 SU Baltimore most recently: When playing on Tuesday are 4-6 Before playing Boston are 4-6 After playing Boston are 2-8 After a loss are 4-6
Boston most recently: When playing on Tuesday are 6-4 Before playing Baltimore are 7-3 After playing Baltimore are 7-3 After a win are 3-7 A few trends to consider: The total has gone OVER in 6 of Baltimore's last 7 games when playing on the road against Boston The total has gone OVER in 4 of Baltimore's last 5 games Baltimore is 5-2 SU in its last 7 games The total has gone OVER in 7 of Baltimore's last 10 games when playing Boston Boston is 7-1 SU in its last 8 games when playing at home against Baltimore The total has gone OVER in 6 of Boston's last 7 games when playing at home against Baltimore Boston is 9-2 SU in its last 11 games when playing Baltimore The total has gone OVER in 10 of Boston's last 14 games Next up: Boston home to Baltimore, Wednesday, September 21 -- You received this message because you are subscribed to the Google Groups "Betting Advice" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/betting-advice?hl=en.
