Courtesy of OddsShark.com The division rival Pittsburgh Steelers and Cincinnati Bengals are set to renew hostilities on Sunday when they meet at Paul Brown Stadium. Oddsmakers currently have the Steelers listed as 3-point favorites versus the Bengals, while the game's total is sitting at 41. The Steelers were a 23-20 loser in their most recent outing at home against the Ravens. They failed to cover the 3.5?point spread as favorites, while the total score (43) made winners of OVER bettors. Cincinnati won its last outing, a 24-17 result against the Titans on November 6. The Bengals covered in that game as a 2.5-point underdog, while the 41 combined points took the game UNDER the total. Current streak: Cincinnati has won 5 straight games. Team records: Pittsburgh: 6-3 SU, 4-5 ATS Cincinnati: 6-2 SU, 7-1 ATS Pittsburgh most recently: When playing in November are 5-5 When playing on turf are 5-5 After outgaining opponent are 8-2 When playing within the division are 7-3
Cincinnati most recently: When playing in November are 4-6 When playing on turf are 5-5 After being outgained are 4-6 When playing within the division are 6-4 A few trends to consider: Pittsburgh is 9-1 SU in its last 10 games when playing on the road against Cincinnati The total has gone OVER in 5 of Pittsburgh's last 6 games on the road Pittsburgh is 4-1 SU in its last 5 games Pittsburgh is 7-2 SU in its last 9 games when playing Cincinnati Cincinnati is 5-0 SU in its last 5 games The total has gone OVER in 4 of Cincinnati's last 5 games Cincinnati is 4-1 SU in its last 5 games at home The total has gone OVER in 6 of Cincinnati's last 8 games at home Next up: Pittsburgh at Kansas City, Sunday, November 27 Cincinnati at Baltimore, Sunday, November 20 -- You received this message because you are subscribed to the Google Groups "Betting Advice" group. To post to this group, send email to [email protected]. To unsubscribe from this group, send email to [email protected]. For more options, visit this group at http://groups.google.com/group/betting-advice?hl=en.
