Well, things are messy, because you haven't carved up your subnet on bit-boundaries. BIND ACLs are either individual IPs, CIDR blocks, negations, or some combination of these. It can be done:
192.168.1.1 through 192.168.1.99 = !192.168.1.0; 192.168.1.0/26; 192.168.1.64/27; 192.168.1.96/30; 192.168.1.100 through 192.168.1.199 = 192.168.1.100/30; 192.168.1.104/29; 192.168.1.112/28; 192.168.1.128/26; 192.168.1.192/29; I might have made an error in the above -- did I mention that this is very error-prone as well? :-) - Kevin -----Original Message----- From: bind-users [mailto:bind-users-boun...@lists.isc.org] On Behalf Of Pol Hallen Sent: Monday, October 17, 2016 2:37 PM To: bind-users@lists.isc.org Subject: defines ip to acl Hello all :-) I need to setup 2 kind of acl on same network, ie: ip from 192.168.1.1 to 192.168.1.99 belongs to acl1 and ip from 192.168.1.100 to 192.168.1.199 to acl2 acl net1 { 192.168.1.1-99/24 }; acl net1 { 192.168.1.99-199/24 }; what's the correct way? I didn't find nothing :-/ thanks for help Pol _______________________________________________ Please visit https://lists.isc.org/mailman/listinfo/bind-users to unsubscribe from this list bind-users mailing list bind-users@lists.isc.org https://lists.isc.org/mailman/listinfo/bind-users _______________________________________________ Please visit https://lists.isc.org/mailman/listinfo/bind-users to unsubscribe from this list bind-users mailing list bind-users@lists.isc.org https://lists.isc.org/mailman/listinfo/bind-users