On Monday, August 5, 2013, David Jeske wrote: > > I see my mis-calculation. AFAIK, if T is a value type, all the above > statements make a copy of T and there is no escaping of the reference. > However, if T is a reference type, they make a copy of the reference to T, > which means the reference of the reference can't escape, but the reference > can. >
Exactly.
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