Agreed, time to put this thread to rest.
I did decide to not pursue trying to increase the designed incline, it is 
not worth the risk of something going wrong.
moderator
----- Original Message ----- 
From: "Dan Rossi" <[EMAIL PROTECTED]>
To: <blindhandyman@yahoogroups.com>
Sent: Sunday, September 14, 2008 3:54 PM
Subject: Re: [BlindHandyMan] tread mill incline


OK Victor, you are correct in that the free end of the treadmill does move
in an arc, but at any point along that arc, you can describe the triangle.
Made by the three points as follows:

1: the stationary end of the treadmill.
2: the point directly below the stationary end, and at the same height of
the opposite end of the treadmill.  IE, that point will move up and down
as the far end of the treadmill moves up and down.
3: the far end of the treadmill.  That point will move up and down, but
will also move in and out as the treadmill moves up and down.
The distance from the fixed point of the treadmill to the point directly
below it is the rise or height of the triangle.

The distance from the free end of the treadmill to the imaginary point
below the fixed end, is the run or base of the triangle.  For small
angles, you can assume that this run is the same length as the treadmill,
60 inches in our example.  However, as the angle increases, the length of
that base leg will actually get shorter.

The hypotenuse of the triangle is the length of the treadmill.  So, for
any given angle, and since you have the hypotenuse, you can get the other
two sides of the triangle.

I think this dead horse is sufficiently beaten now.

  -- 
Blue skies.
Dan Rossi
Carnegie Mellon University.
E-Mail: [EMAIL PROTECTED]
Tel: (412) 268-9081

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