On Sat, 07 Dec 2002 17:16:42 +0100, Gennaro Prota <[EMAIL PROTECTED]> wrote:
>On 07 Dec 2002 12:26:35 +0100, Gabriel Dos Reis ><[EMAIL PROTECTED]> wrote: > > >>5.2.10/1: >> The result of the expression reinterpret_cast<T>(v) is the result of >> converting the expression v to type T. [...] > >Are you saying you really understand what that phrase means? To avoid a possible misunderstanding: I was not attacking you, that would be the last straw. It's _the sentence_ that is IMHO a little meaningless; I think it's just a rough, informal description (sort of preamble) of what is specified in the subsequent paragraphs. Well, in fact those subsequent paragraphs intentionally give very few guarantee, and reinterpret_cast<void*> is exactly one of the cases which are left unspecified (the guarantee of 5.2.10/7 concerns casting to pointers to *object types*). So I guess there's not much room for proving your equivalence. Genny. _______________________________________________ Unsubscribe & other changes: http://lists.boost.org/mailman/listinfo.cgi/boost
