From: "Fernando Cacciola" <[EMAIL PROTECTED]>
> The conversion to bool for a smart pointer unambiguously refers to the
> NULL state of the pointer wrapped.
> In the case of optional, a conversion to bool will be ambiguous in those
> cases were the wrapped T in optional<> is bool itself.
On the other hand, it would enable the useful idiom
if(optional<T> pt = get_optional_T())
{
// use *pt
}
I don't think that optional<bool> is an important use case (outside of
generic contexts) since optional<bool> is simply a tri-state type with an
inconvenient interface.
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