You can turn on the literal flag type. All characters in your regular expression are treated as literals.
That doesn't help. Maybe an example clarifies what I need:
std::string s = "1.30.0"; boost::regex r( "^(.*)\s+(?:[Vv](?:ersion)?\s+" + s + ")\s*$" );
I need a way to convert 's' to '1\.30\.0', not to escape the whole regex.
Regards, Daniel
-- Daniel Frey
aixigo AG - financial training, research and technology Schloß-Rahe-Straße 15, 52072 Aachen, Germany fon: +49 (0)241 936737-42, fax: +49 (0)241 936737-99 eMail: [EMAIL PROTECTED], web: http://www.aixigo.de
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